8(y-7)=-2(y-3)

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Solution for 8(y-7)=-2(y-3) equation: 



8(y-7)=-2(y-3)

We move all terms to the left:

8(y-7)-(-2(y-3))=0

We multiply parentheses

8y-(-2(y-3))-56=0



We calculate terms in parentheses: -(-2(y-3)), so:

-2(y-3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We get rid of parentheses

8y+2y-6-56=0

We add all the numbers together, and all the variables

10y-62=0

We move all terms containing y to the left, all other terms to the right

10y=62

y=62/10

y=6+1/5

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