8(y-3)+2(3y+5)=6y+26

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Solution for 8(y-3)+2(3y+5)=6y+26 equation: 



8(y-3)+2(3y+5)=6y+26

We move all terms to the left:

8(y-3)+2(3y+5)-(6y+26)=0

We multiply parentheses

8y+6y-(6y+26)-24+10=0

We get rid of parentheses

8y+6y-6y-26-24+10=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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