8(y-2)=5(y+3)+8

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Solution for 8(y-2)=5(y+3)+8 equation: 



8(y-2)=5(y+3)+8

We move all terms to the left:

8(y-2)-(5(y+3)+8)=0

We multiply parentheses

8y-(5(y+3)+8)-16=0



We calculate terms in parentheses: -(5(y+3)+8), so:

5(y+3)+8

We multiply parentheses

5y+15+8

We add all the numbers together, and all the variables

5y+23

Back to the equation:

-(5y+23)



We get rid of parentheses

8y-5y-23-16=0

We add all the numbers together, and all the variables

3y-39=0

We move all terms containing y to the left, all other terms to the right

3y=39

y=39/3

y=13

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