8(y-1)-4=4(2y-3)

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Solution for 8(y-1)-4=4(2y-3) equation: 


Simplifying
8(y + -1) + -4 = 4(2y + -3)

Reorder the terms:
8(-1 + y) + -4 = 4(2y + -3)
(-1 * 8 + y * 8) + -4 = 4(2y + -3)
(-8 + 8y) + -4 = 4(2y + -3)

Reorder the terms:
-8 + -4 + 8y = 4(2y + -3)

Combine like terms: -8 + -4 = -12
-12 + 8y = 4(2y + -3)

Reorder the terms:
-12 + 8y = 4(-3 + 2y)
-12 + 8y = (-3 * 4 + 2y * 4)
-12 + 8y = (-12 + 8y)

Add '12' to each side of the equation.
-12 + 12 + 8y = -12 + 12 + 8y

Combine like terms: -12 + 12 = 0
0 + 8y = -12 + 12 + 8y
8y = -12 + 12 + 8y

Combine like terms: -12 + 12 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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