8(y+8)-2(y-3)=3(y-4)

Solution for 8(y+8)-2(y-3)=3(y-4) equation:

8(y+8)-2(y-3)=3(y-4)

We move all terms to the left:

8(y+8)-2(y-3)-(3(y-4))=0

We multiply parentheses

8y-2y-(3(y-4))+64+6=0


We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)


We add all the numbers together, and all the variables

6y-(3y-12)+70=0

We get rid of parentheses

6y-3y+12+70=0

We add all the numbers together, and all the variables

3y+82=0

We move all terms containing y to the left, all other terms to the right

3y=-82

y=-82/3

y=-27+1/3