8(y+4)-(7y-9)=3

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Solution for 8(y+4)-(7y-9)=3 equation: 



8(y+4)-(7y-9)=3

We move all terms to the left:

8(y+4)-(7y-9)-(3)=0

We multiply parentheses

8y-(7y-9)+32-3=0

We get rid of parentheses

8y-7y+9+32-3=0

We add all the numbers together, and all the variables

y+38=0

We move all terms containing y to the left, all other terms to the right

y=-38

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