8(y+2)=4(y-3)

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Solution for 8(y+2)=4(y-3) equation: 


Simplifying
8(y + 2) = 4(y + -3)

Reorder the terms:
8(2 + y) = 4(y + -3)
(2 * 8 + y * 8) = 4(y + -3)
(16 + 8y) = 4(y + -3)

Reorder the terms:
16 + 8y = 4(-3 + y)
16 + 8y = (-3 * 4 + y * 4)
16 + 8y = (-12 + 4y)

Solving
16 + 8y = -12 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
16 + 8y + -4y = -12 + 4y + -4y

Combine like terms: 8y + -4y = 4y
16 + 4y = -12 + 4y + -4y

Combine like terms: 4y + -4y = 0
16 + 4y = -12 + 0
16 + 4y = -12

Add '-16' to each side of the equation.
16 + -16 + 4y = -12 + -16

Combine like terms: 16 + -16 = 0
0 + 4y = -12 + -16
4y = -12 + -16

Combine like terms: -12 + -16 = -28
4y = -28

Divide each side by '4'.
y = -7

Simplifying
y = -7

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