8(y+2)=4(1+3y)

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Solution for 8(y+2)=4(1+3y) equation: 



8(y+2)=4(1+3y)

We move all terms to the left:

8(y+2)-(4(1+3y))=0

We add all the numbers together, and all the variables

8(y+2)-(4(3y+1))=0

We multiply parentheses

8y-(4(3y+1))+16=0



We calculate terms in parentheses: -(4(3y+1)), so:

4(3y+1)

We multiply parentheses

12y+4

Back to the equation:

-(12y+4)



We get rid of parentheses

8y-12y-4+16=0

We add all the numbers together, and all the variables

-4y+12=0

We move all terms containing y to the left, all other terms to the right

-4y=-12

y=-12/-4

y=+3

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