8(y+2)=-3y+38

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Solution for 8(y+2)=-3y+38 equation: 



8(y+2)=-3y+38

We move all terms to the left:

8(y+2)-(-3y+38)=0

We multiply parentheses

8y-(-3y+38)+16=0

We get rid of parentheses

8y+3y-38+16=0

We add all the numbers together, and all the variables

11y-22=0

We move all terms containing y to the left, all other terms to the right

11y=22

y=22/11

y=2

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