8(y+2)-3(y-4)=5(y-7)+8

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Solution for 8(y+2)-3(y-4)=5(y-7)+8 equation: 



8(y+2)-3(y-4)=5(y-7)+8

We move all terms to the left:

8(y+2)-3(y-4)-(5(y-7)+8)=0

We multiply parentheses

8y-3y-(5(y-7)+8)+16+12=0



We calculate terms in parentheses: -(5(y-7)+8), so:

5(y-7)+8

We multiply parentheses

5y-35+8

We add all the numbers together, and all the variables

5y-27

Back to the equation:

-(5y-27)



We add all the numbers together, and all the variables

5y-(5y-27)+28=0

We get rid of parentheses

5y-5y+27+28=0

We add all the numbers together, and all the variables

55!=0

There is no solution for this equation

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