8(y+1)=4y+48

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Solution for 8(y+1)=4y+48 equation: 



8(y+1)=4y+48

We move all terms to the left:

8(y+1)-(4y+48)=0

We multiply parentheses

8y-(4y+48)+8=0

We get rid of parentheses

8y-4y-48+8=0

We add all the numbers together, and all the variables

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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