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8(x-9)=6(2x-12)-3x
We move all terms to the left:
8(x-9)-(6(2x-12)-3x)=0
We multiply parentheses
8x-(6(2x-12)-3x)-72=0
We calculate terms in parentheses: -(6(2x-12)-3x), so:We get rid of parentheses
6(2x-12)-3x
We add all the numbers together, and all the variables
-3x+6(2x-12)
We multiply parentheses
-3x+12x-72
We add all the numbers together, and all the variables
9x-72
Back to the equation:
-(9x-72)
8x-9x+72-72=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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