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8(x-5)=(x+2)
We move all terms to the left:
8(x-5)-((x+2))=0
We multiply parentheses
8x-((x+2))-40=0
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
8x-x-2-40=0
We add all the numbers together, and all the variables
7x-42=0
We move all terms containing x to the left, all other terms to the right
7x=42
x=42/7
x=6
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