8(x-4)-2=7(x-1)

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Solution for 8(x-4)-2=7(x-1) equation: 



8(x-4)-2=7(x-1)

We move all terms to the left:

8(x-4)-2-(7(x-1))=0

We multiply parentheses

8x-(7(x-1))-32-2=0



We calculate terms in parentheses: -(7(x-1)), so:

7(x-1)

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

8x-(7x-7)-34=0

We get rid of parentheses

8x-7x+7-34=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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