8(x-4)+10=5(3-2x)-1

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Solution for 8(x-4)+10=5(3-2x)-1 equation: 



8(x-4)+10=5(3-2x)-1

We move all terms to the left:

8(x-4)+10-(5(3-2x)-1)=0

We add all the numbers together, and all the variables

8(x-4)-(5(-2x+3)-1)+10=0

We multiply parentheses

8x-(5(-2x+3)-1)-32+10=0



We calculate terms in parentheses: -(5(-2x+3)-1), so:

5(-2x+3)-1

We multiply parentheses

-10x+15-1

We add all the numbers together, and all the variables

-10x+14

Back to the equation:

-(-10x+14)



We add all the numbers together, and all the variables

8x-(-10x+14)-22=0

We get rid of parentheses

8x+10x-14-22=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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