8(x-3)=8x-(4x+12)

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Solution for 8(x-3)=8x-(4x+12) equation: 



8(x-3)=8x-(4x+12)

We move all terms to the left:

8(x-3)-(8x-(4x+12))=0

We multiply parentheses

8x-(8x-(4x+12))-24=0



We calculate terms in parentheses: -(8x-(4x+12)), so:

8x-(4x+12)

We get rid of parentheses

8x-4x-12

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

8x-4x+12-24=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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