8(x-3)-3x=2(x+12)+7x

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Solution for 8(x-3)-3x=2(x+12)+7x equation: 



8(x-3)-3x=2(x+12)+7x

We move all terms to the left:

8(x-3)-3x-(2(x+12)+7x)=0

We add all the numbers together, and all the variables

-3x+8(x-3)-(2(x+12)+7x)=0

We multiply parentheses

-3x+8x-(2(x+12)+7x)-24=0



We calculate terms in parentheses: -(2(x+12)+7x), so:

2(x+12)+7x

We add all the numbers together, and all the variables

7x+2(x+12)

We multiply parentheses

7x+2x+24

We add all the numbers together, and all the variables

9x+24

Back to the equation:

-(9x+24)



We add all the numbers together, and all the variables

5x-(9x+24)-24=0

We get rid of parentheses

5x-9x-24-24=0

We add all the numbers together, and all the variables

-4x-48=0

We move all terms containing x to the left, all other terms to the right

-4x=48

x=48/-4

x=-12

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