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8(x-3)-(6-2x)=2(x+2)
We move all terms to the left:
8(x-3)-(6-2x)-(2(x+2))=0
We add all the numbers together, and all the variables
8(x-3)-(-2x+6)-(2(x+2))=0
We multiply parentheses
8x-(-2x+6)-(2(x+2))-24=0
We get rid of parentheses
8x+2x-(2(x+2))-6-24=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
10x-(2x+4)-30=0
We get rid of parentheses
10x-2x-4-30=0
We add all the numbers together, and all the variables
8x-34=0
We move all terms containing x to the left, all other terms to the right
8x=34
x=34/8
x=4+1/4
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