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8(x-2)=3(2-x)
We move all terms to the left:
8(x-2)-(3(2-x))=0
We add all the numbers together, and all the variables
8(x-2)-(3(-1x+2))=0
We multiply parentheses
8x-(3(-1x+2))-16=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
8x+3x-6-16=0
We add all the numbers together, and all the variables
11x-22=0
We move all terms containing x to the left, all other terms to the right
11x=22
x=22/11
x=2
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