8(x-2)=-6(x+1)+40

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Solution for 8(x-2)=-6(x+1)+40 equation: 



8(x-2)=-6(x+1)+40

We move all terms to the left:

8(x-2)-(-6(x+1)+40)=0

We multiply parentheses

8x-(-6(x+1)+40)-16=0



We calculate terms in parentheses: -(-6(x+1)+40), so:

-6(x+1)+40

We multiply parentheses

-6x-6+40

We add all the numbers together, and all the variables

-6x+34

Back to the equation:

-(-6x+34)



We get rid of parentheses

8x+6x-34-16=0

We add all the numbers together, and all the variables

14x-50=0

We move all terms containing x to the left, all other terms to the right

14x=50

x=50/14

x=3+4/7

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