8(x-2)2+4x=3(x+4)+7x+2

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Solution for 8(x-2)2+4x=3(x+4)+7x+2 equation: 



8(x-2)2+4x=3(x+4)+7x+2

We move all terms to the left:

8(x-2)2+4x-(3(x+4)+7x+2)=0

We add all the numbers together, and all the variables

4x+8(x-2)2-(3(x+4)+7x+2)=0

We multiply parentheses

4x+16x-(3(x+4)+7x+2)-32=0



We calculate terms in parentheses: -(3(x+4)+7x+2), so:

3(x+4)+7x+2

We add all the numbers together, and all the variables

7x+3(x+4)+2

We multiply parentheses

7x+3x+12+2

We add all the numbers together, and all the variables

10x+14

Back to the equation:

-(10x+14)



We add all the numbers together, and all the variables

20x-(10x+14)-32=0

We get rid of parentheses

20x-10x-14-32=0

We add all the numbers together, and all the variables

10x-46=0

We move all terms containing x to the left, all other terms to the right

10x=46

x=46/10

x=4+3/5

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