8(x-2)-3(1-x)=9(x+2+1)

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Solution for 8(x-2)-3(1-x)=9(x+2+1) equation: 



8(x-2)-3(1-x)=9(x+2+1)

We move all terms to the left:

8(x-2)-3(1-x)-(9(x+2+1))=0

We add all the numbers together, and all the variables

8(x-2)-3(-1x+1)-(9(x+3))=0

We multiply parentheses

8x+3x-(9(x+3))-16-3=0



We calculate terms in parentheses: -(9(x+3)), so:

9(x+3)

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We add all the numbers together, and all the variables

11x-(9x+27)-19=0

We get rid of parentheses

11x-9x-27-19=0

We add all the numbers together, and all the variables

2x-46=0

We move all terms containing x to the left, all other terms to the right

2x=46

x=46/2

x=23

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