8(x-1)=4(x+2)

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Solution for 8(x-1)=4(x+2) equation: 



8(x-1)=4(x+2)

We move all terms to the left:

8(x-1)-(4(x+2))=0

We multiply parentheses

8x-(4(x+2))-8=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

8x-4x-8-8=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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