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8(x-1)=3(4+2x)
We move all terms to the left:
8(x-1)-(3(4+2x))=0
We add all the numbers together, and all the variables
8(x-1)-(3(2x+4))=0
We multiply parentheses
8x-(3(2x+4))-8=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
8x-6x-12-8=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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