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8(x+5)=2(3x-10)
We move all terms to the left:
8(x+5)-(2(3x-10))=0
We multiply parentheses
8x-(2(3x-10))+40=0
We calculate terms in parentheses: -(2(3x-10)), so:We get rid of parentheses
2(3x-10)
We multiply parentheses
6x-20
Back to the equation:
-(6x-20)
8x-6x+20+40=0
We add all the numbers together, and all the variables
2x+60=0
We move all terms containing x to the left, all other terms to the right
2x=-60
x=-60/2
x=-30
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