8(x+4)=7x-2+40

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Solution for 8(x+4)=7x-2+40 equation: 



8(x+4)=7x-2+40

We move all terms to the left:

8(x+4)-(7x-2+40)=0

We add all the numbers together, and all the variables

8(x+4)-(7x+38)=0

We multiply parentheses

8x-(7x+38)+32=0

We get rid of parentheses

8x-7x-38+32=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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