8(x+4)=10x-(2x+8)+40

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Solution for 8(x+4)=10x-(2x+8)+40 equation: 



8(x+4)=10x-(2x+8)+40

We move all terms to the left:

8(x+4)-(10x-(2x+8)+40)=0

We multiply parentheses

8x-(10x-(2x+8)+40)+32=0



We calculate terms in parentheses: -(10x-(2x+8)+40), so:

10x-(2x+8)+40

We get rid of parentheses

10x-2x-8+40

We add all the numbers together, and all the variables

8x+32

Back to the equation:

-(8x+32)



We get rid of parentheses

8x-8x-32+32=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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