8(x+4)+3=-6(x-5)-3

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Solution for 8(x+4)+3=-6(x-5)-3 equation:



8(x+4)+3=-6(x-5)-3
We move all terms to the left:
8(x+4)+3-(-6(x-5)-3)=0
We multiply parentheses
8x-(-6(x-5)-3)+32+3=0
We calculate terms in parentheses: -(-6(x-5)-3), so:
-6(x-5)-3
We multiply parentheses
-6x+30-3
We add all the numbers together, and all the variables
-6x+27
Back to the equation:
-(-6x+27)
We add all the numbers together, and all the variables
8x-(-6x+27)+35=0
We get rid of parentheses
8x+6x-27+35=0
We add all the numbers together, and all the variables
14x+8=0
We move all terms containing x to the left, all other terms to the right
14x=-8
x=-8/14
x=-4/7

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