8(x+3)+8=10x-2(x-5)

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Solution for 8(x+3)+8=10x-2(x-5) equation: 



8(x+3)+8=10x-2(x-5)

We move all terms to the left:

8(x+3)+8-(10x-2(x-5))=0

We multiply parentheses

8x-(10x-2(x-5))+24+8=0



We calculate terms in parentheses: -(10x-2(x-5)), so:

10x-2(x-5)

We multiply parentheses

10x-2x+10

We add all the numbers together, and all the variables

8x+10

Back to the equation:

-(8x+10)



We add all the numbers together, and all the variables

8x-(8x+10)+32=0

We get rid of parentheses

8x-8x-10+32=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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