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8(x+2)=4(2x+4)
We move all terms to the left:
8(x+2)-(4(2x+4))=0
We multiply parentheses
8x-(4(2x+4))+16=0
We calculate terms in parentheses: -(4(2x+4)), so:We get rid of parentheses
4(2x+4)
We multiply parentheses
8x+16
Back to the equation:
-(8x+16)
8x-8x-16+16=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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