8(x+2)=4(2x+1)+12

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Solution for 8(x+2)=4(2x+1)+12 equation:


Simplifying
8(x + 2) = 4(2x + 1) + 12

Reorder the terms:
8(2 + x) = 4(2x + 1) + 12
(2 * 8 + x * 8) = 4(2x + 1) + 12
(16 + 8x) = 4(2x + 1) + 12

Reorder the terms:
16 + 8x = 4(1 + 2x) + 12
16 + 8x = (1 * 4 + 2x * 4) + 12
16 + 8x = (4 + 8x) + 12

Reorder the terms:
16 + 8x = 4 + 12 + 8x

Combine like terms: 4 + 12 = 16
16 + 8x = 16 + 8x

Add '-16' to each side of the equation.
16 + -16 + 8x = 16 + -16 + 8x

Combine like terms: 16 + -16 = 0
0 + 8x = 16 + -16 + 8x
8x = 16 + -16 + 8x

Combine like terms: 16 + -16 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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