8(x+2)=2(x-1)

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Solution for 8(x+2)=2(x-1) equation: 



8(x+2)=2(x-1)

We move all terms to the left:

8(x+2)-(2(x-1))=0

We multiply parentheses

8x-(2(x-1))+16=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

8x-2x+2+16=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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