8(x+2)-6=6(2x-1)+6

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Solution for 8(x+2)-6=6(2x-1)+6 equation: 



8(x+2)-6=6(2x-1)+6

We move all terms to the left:

8(x+2)-6-(6(2x-1)+6)=0

We multiply parentheses

8x-(6(2x-1)+6)+16-6=0



We calculate terms in parentheses: -(6(2x-1)+6), so:

6(2x-1)+6

We multiply parentheses

12x-6+6

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



We add all the numbers together, and all the variables

-4x+10=0

We move all terms containing x to the left, all other terms to the right

-4x=-10

x=-10/-4

x=2+1/2

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