8(x+2)-5=6(x+1)+23

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Solution for 8(x+2)-5=6(x+1)+23 equation: 



8(x+2)-5=6(x+1)+23

We move all terms to the left:

8(x+2)-5-(6(x+1)+23)=0

We multiply parentheses

8x-(6(x+1)+23)+16-5=0



We calculate terms in parentheses: -(6(x+1)+23), so:

6(x+1)+23

We multiply parentheses

6x+6+23

We add all the numbers together, and all the variables

6x+29

Back to the equation:

-(6x+29)



We add all the numbers together, and all the variables

8x-(6x+29)+11=0

We get rid of parentheses

8x-6x-29+11=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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