8(x+2)-3(x-4)=6(x=7)+8

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Solution for 8(x+2)-3(x-4)=6(x=7)+8 equation: 



8(x+2)-3(x-4)=6(x=7)+8

We move all terms to the left:

8(x+2)-3(x-4)-(6(x)=0

We multiply parentheses

8x-3x-(6x+16+12=0

We add all the numbers together, and all the variables

5x-(6x+16+12=0

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