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8(x+12)=12(x)
We move all terms to the left:
8(x+12)-(12(x))=0
determiningTheFunctionDomain 8(x+12)-12x=0
We add all the numbers together, and all the variables
-12x+8(x+12)=0
We multiply parentheses
-12x+8x+96=0
We add all the numbers together, and all the variables
-4x+96=0
We move all terms containing x to the left, all other terms to the right
-4x=-96
x=-96/-4
x=+24
| -15x+10x=15(2x-5) | | 25=s3− –15 | | -10-3t=-2t | | 4x+39=87 | | -9a-26=-46-7a | | 2z+3z-6=9 |