8(x+10)=8+3(2x-2)

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Solution for 8(x+10)=8+3(2x-2) equation: 



8(x+10)=8+3(2x-2)

We move all terms to the left:

8(x+10)-(8+3(2x-2))=0

We multiply parentheses

8x-(8+3(2x-2))+80=0



We calculate terms in parentheses: -(8+3(2x-2)), so:

8+3(2x-2)

determiningTheFunctionDomain
3(2x-2)+8

We multiply parentheses

6x-6+8

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

8x-6x-2+80=0

We add all the numbers together, and all the variables

2x+78=0

We move all terms containing x to the left, all other terms to the right

2x=-78

x=-78/2

x=-39

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