8(x+10)+2=-4(x-4)-10

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Solution for 8(x+10)+2=-4(x-4)-10 equation: 



8(x+10)+2=-4(x-4)-10

We move all terms to the left:

8(x+10)+2-(-4(x-4)-10)=0

We multiply parentheses

8x-(-4(x-4)-10)+80+2=0



We calculate terms in parentheses: -(-4(x-4)-10), so:

-4(x-4)-10

We multiply parentheses

-4x+16-10

We add all the numbers together, and all the variables

-4x+6

Back to the equation:

-(-4x+6)



We add all the numbers together, and all the variables

8x-(-4x+6)+82=0

We get rid of parentheses

8x+4x-6+82=0

We add all the numbers together, and all the variables

12x+76=0

We move all terms containing x to the left, all other terms to the right

12x=-76

x=-76/12

x=-6+1/3

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