8(x+1)=4(3x-2)

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Solution for 8(x+1)=4(3x-2) equation:



8(x+1)=4(3x-2)
We move all terms to the left:
8(x+1)-(4(3x-2))=0
We multiply parentheses
8x-(4(3x-2))+8=0
We calculate terms in parentheses: -(4(3x-2)), so:
4(3x-2)
We multiply parentheses
12x-8
Back to the equation:
-(12x-8)
We get rid of parentheses
8x-12x+8+8=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4

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