8(x+1)=12(x-4)

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Solution for 8(x+1)=12(x-4) equation: 



8(x+1)=12(x-4)

We move all terms to the left:

8(x+1)-(12(x-4))=0

We multiply parentheses

8x-(12(x-4))+8=0



We calculate terms in parentheses: -(12(x-4)), so:

12(x-4)

We multiply parentheses

12x-48

Back to the equation:

-(12x-48)



We get rid of parentheses

8x-12x+48+8=0

We add all the numbers together, and all the variables

-4x+56=0

We move all terms containing x to the left, all other terms to the right

-4x=-56

x=-56/-4

x=+14

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