8(x+1)-7=6x+2(1+x)

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Solution for 8(x+1)-7=6x+2(1+x) equation: 



8(x+1)-7=6x+2(1+x)

We move all terms to the left:

8(x+1)-7-(6x+2(1+x))=0

We add all the numbers together, and all the variables

8(x+1)-(6x+2(x+1))-7=0

We multiply parentheses

8x-(6x+2(x+1))+8-7=0



We calculate terms in parentheses: -(6x+2(x+1)), so:

6x+2(x+1)

We multiply parentheses

6x+2x+2

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

8x-(8x+2)+1=0

We get rid of parentheses

8x-8x-2+1=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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