8(x+1)-6=3(8-x)+1

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Solution for 8(x+1)-6=3(8-x)+1 equation: 



8(x+1)-6=3(8-x)+1

We move all terms to the left:

8(x+1)-6-(3(8-x)+1)=0

We add all the numbers together, and all the variables

8(x+1)-(3(-1x+8)+1)-6=0

We multiply parentheses

8x-(3(-1x+8)+1)+8-6=0



We calculate terms in parentheses: -(3(-1x+8)+1), so:

3(-1x+8)+1

We multiply parentheses

-3x+24+1

We add all the numbers together, and all the variables

-3x+25

Back to the equation:

-(-3x+25)



We add all the numbers together, and all the variables

8x-(-3x+25)+2=0

We get rid of parentheses

8x+3x-25+2=0

We add all the numbers together, and all the variables

11x-23=0

We move all terms containing x to the left, all other terms to the right

11x=23

x=23/11

x=2+1/11

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