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8(x+1)-2x=3(2x+1)
We move all terms to the left:
8(x+1)-2x-(3(2x+1))=0
We add all the numbers together, and all the variables
-2x+8(x+1)-(3(2x+1))=0
We multiply parentheses
-2x+8x-(3(2x+1))+8=0
We calculate terms in parentheses: -(3(2x+1)), so:We add all the numbers together, and all the variables
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
6x-(6x+3)+8=0
We get rid of parentheses
6x-6x-3+8=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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