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8(x+1)-1=2x+6(2+x)
We move all terms to the left:
8(x+1)-1-(2x+6(2+x))=0
We add all the numbers together, and all the variables
8(x+1)-(2x+6(x+2))-1=0
We multiply parentheses
8x-(2x+6(x+2))+8-1=0
We calculate terms in parentheses: -(2x+6(x+2)), so:We add all the numbers together, and all the variables
2x+6(x+2)
We multiply parentheses
2x+6x+12
We add all the numbers together, and all the variables
8x+12
Back to the equation:
-(8x+12)
8x-(8x+12)+7=0
We get rid of parentheses
8x-8x-12+7=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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