8(x+-9)=6(2x+-12)+-4x

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Solution for 8(x+-9)=6(2x+-12)+-4x equation: 



8(x+-9)=6(2x+-12)+-4x

We move all terms to the left:

8(x+-9)-(6(2x+-12)+-4x)=0

We add all the numbers together, and all the variables

8(x-9)-(6(2x-12)+-4x)=0

We use the square of the difference formula

8(x-9)-(6(2x-12)-4x)=0

We multiply parentheses

8x-(6(2x-12)-4x)-72=0



We calculate terms in parentheses: -(6(2x-12)-4x), so:

6(2x-12)-4x

We add all the numbers together, and all the variables

-4x+6(2x-12)

We multiply parentheses

-4x+12x-72

We add all the numbers together, and all the variables

8x-72

Back to the equation:

-(8x-72)



We get rid of parentheses

8x-8x+72-72=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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