8(x+-1)-6=-3(8-x)+1

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Solution for 8(x+-1)-6=-3(8-x)+1 equation: 



8(x+-1)-6=-3(8-x)+1

We move all terms to the left:

8(x+-1)-6-(-3(8-x)+1)=0

We add all the numbers together, and all the variables

8(x-1)-(-3(-1x+8)+1)-6=0

We multiply parentheses

8x-(-3(-1x+8)+1)-8-6=0



We calculate terms in parentheses: -(-3(-1x+8)+1), so:

-3(-1x+8)+1

We multiply parentheses

3x-24+1

We add all the numbers together, and all the variables

3x-23

Back to the equation:

-(3x-23)



We add all the numbers together, and all the variables

8x-(3x-23)-14=0

We get rid of parentheses

8x-3x+23-14=0

We add all the numbers together, and all the variables

5x+9=0

We move all terms containing x to the left, all other terms to the right

5x=-9

x=-9/5

x=-1+4/5

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