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8(v+6)=3-(-8v-45)
We move all terms to the left:
8(v+6)-(3-(-8v-45))=0
We multiply parentheses
8v-(3-(-8v-45))+48=0
We calculate terms in parentheses: -(3-(-8v-45)), so:We get rid of parentheses
3-(-8v-45)
determiningTheFunctionDomain -(-8v-45)+3
We get rid of parentheses
8v+45+3
We add all the numbers together, and all the variables
8v+48
Back to the equation:
-(8v+48)
8v-8v-48+48=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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