8(v+2)-4v=2(2v+2)-13

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Solution for 8(v+2)-4v=2(2v+2)-13 equation:


Simplifying
8(v + 2) + -4v = 2(2v + 2) + -13

Reorder the terms:
8(2 + v) + -4v = 2(2v + 2) + -13
(2 * 8 + v * 8) + -4v = 2(2v + 2) + -13
(16 + 8v) + -4v = 2(2v + 2) + -13

Combine like terms: 8v + -4v = 4v
16 + 4v = 2(2v + 2) + -13

Reorder the terms:
16 + 4v = 2(2 + 2v) + -13
16 + 4v = (2 * 2 + 2v * 2) + -13
16 + 4v = (4 + 4v) + -13

Reorder the terms:
16 + 4v = 4 + -13 + 4v

Combine like terms: 4 + -13 = -9
16 + 4v = -9 + 4v

Add '-4v' to each side of the equation.
16 + 4v + -4v = -9 + 4v + -4v

Combine like terms: 4v + -4v = 0
16 + 0 = -9 + 4v + -4v
16 = -9 + 4v + -4v

Combine like terms: 4v + -4v = 0
16 = -9 + 0
16 = -9

Solving
16 = -9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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