8(v+2)-2v=2(3v+3)-12

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Solution for 8(v+2)-2v=2(3v+3)-12 equation: 



8(v+2)-2v=2(3v+3)-12

We move all terms to the left:

8(v+2)-2v-(2(3v+3)-12)=0

We add all the numbers together, and all the variables

-2v+8(v+2)-(2(3v+3)-12)=0

We multiply parentheses

-2v+8v-(2(3v+3)-12)+16=0



We calculate terms in parentheses: -(2(3v+3)-12), so:

2(3v+3)-12

We multiply parentheses

6v+6-12

We add all the numbers together, and all the variables

6v-6

Back to the equation:

-(6v-6)



We add all the numbers together, and all the variables

6v-(6v-6)+16=0

We get rid of parentheses

6v-6v+6+16=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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