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8(v+1)-2v=3(2v+4)-16
We move all terms to the left:
8(v+1)-2v-(3(2v+4)-16)=0
We add all the numbers together, and all the variables
-2v+8(v+1)-(3(2v+4)-16)=0
We multiply parentheses
-2v+8v-(3(2v+4)-16)+8=0
We calculate terms in parentheses: -(3(2v+4)-16), so:We add all the numbers together, and all the variables
3(2v+4)-16
We multiply parentheses
6v+12-16
We add all the numbers together, and all the variables
6v-4
Back to the equation:
-(6v-4)
6v-(6v-4)+8=0
We get rid of parentheses
6v-6v+4+8=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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